x^2-27+6=(x-3)(x+9)

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Solution for x^2-27+6=(x-3)(x+9) equation: 



x^2-27+6=(x-3)(x+9)

We move all terms to the left:

x^2-27+6-((x-3)(x+9))=0

We add all the numbers together, and all the variables

x^2-((x-3)(x+9))-21=0

We multiply parentheses ..

x^2-((+x^2+9x-3x-27))-21=0



We calculate terms in parentheses: -((+x^2+9x-3x-27)), so:

(+x^2+9x-3x-27)

We get rid of parentheses

x^2+9x-3x-27

We add all the numbers together, and all the variables

x^2+6x-27

Back to the equation:

-(x^2+6x-27)



We get rid of parentheses

x^2-x^2-6x+27-21=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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